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Question 1:

Which three statements are true regarding the SQL WHERE and HAVING clauses?

A. The HAVING clause conditions can have aggregating functions.

B. The HAVING clause conditions can use aliases for the columns.

C. The WHERE and HAVING clauses cannot be used together in a SQL statement.

D. The WHERE clause is used to exclude rows before grouping data.

E. The HAVING clause is used to exclude one or more aggregated results after grouping data.

Correct Answer: ADE


Question 2:

Examine the structure of the MEMBERS table. NameNull?Type

MEMBER_IDNOT NULLVARCHAR2 (6)

FIRST_NAMEVARCHAR2 (50)

LAST_NAMENOT NULLVARCHAR2 (50)

ADDRESSVARCHAR2 (50)

CITYVARCHAR2 (25)

STATENOT NULL VARCHAR2 (3)

Which query can be used to display the last names and city names only for members from the states MO and MI?

A. SELECT last_name, city FROM members WHERE state =\’MO\’ AND state =\’MI\’;

B. SELECT last_name, city FROM members WHERE state LIKE \’M%\’;

C. SELECT last_name, city FROM members WHERE state IN (\’MO\’, \’MI\’);

D. SELECT DISTINCT last_name, city FROM members WHERE state =\’MO\’ OR state =\’MI\’;

Correct Answer: C


Question 3:

Which two are the minimal requirements for a self-join? (Choose two.)

A. Only equijoin conditions may be used in the query.

B. Outer joins must not be used in the query.

C. There must be a condition on which the self-join is performed.

D. No other condition except the self-join may be specified.

E. The table used for the self-join must have two different alias names in the query.

Correct Answer: CE


Question 4:

Which three statements are true regarding the data types?

A. The minimum column width that can be specified for a VARCHAR2 data type column is one.

B. Only one LONG column can be used per table.

C. A TIMESTAMP data type column stores only time values with fractional seconds.

D. The BLOB data type column is used to store binary data in an operating system file.

E. The value for a CHAR data type column is blank-padded to the maximum defined column width.

Correct Answer: ABE


Question 5:

View the Exhibit and examine the details of the PRODUCT_INFORMATION table.

You have the requirement to display PRODUCT_NAME and LIST_PRICE from the table where the CATEGORYJD column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL

statement:

SELECT product_name, list_price

FROM product_information

WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088;

Which statement is true regarding the execution of the query?

A. It would execute but the output would return no rows.

B. It would execute and the output would display the desired result.

C. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.

D. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.

Correct Answer: A


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Question 6:

View the exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES NameNull?Type

EMPLOYEE_IDNOT NULLNUMBER(6)

FIRST_NAMEVARCHAR2(20)

LAST_NAMENOT NULLVARCHAR2(25)

HIRE_DATENOT NULLDATE

JOB_IDNOT NULLVARCHAR2(10)

SALARYNUMBER(10,2)

COMMISSIONNUMBER(6,2)

MANAGER_IDNUMBER(6)

DEPARTMENT_IDNUMBER(4)

DEPARTMENTS

NameNull?Type

DEPARTMENT_IDNOT NULLNUMBER(4) DEPARTMENT_NAMENOT NULLVARCHAR2(30)

MANAGER_IDNUMBER(6)

LOCATION_IDNUMBER(4)

You want to update EMPLOYEES table as follows:

You issue the following command:

SQL> UPDATE employees

SET department_id =

(SELECT department_id

FROM departments

WHERE location_id = 2100),

(salary, commission) =

(SELECT 1.1*AVG(salary), 1.5*AVG(commission)

FROM employees, departments

WHERE departments.location_id IN(2900, 2700, 2100))

WHERE department_id IN

(SELECT department_id

FROM departments

WHERE location_id = 2900

OR location_id = 2700;

What is outcome?

A. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an UPDATE statement.

B. It generates an error because a subquery cannot have a join condition in a UPDATE statement.

C. It executes successfully and gives the desired update

D. It executes successfully but does not give the desired update

Correct Answer: D


Question 7:

Examine the structure of the MEMBERS table: NameNull-Type

MEMBER_IDNOT NULLVARCHAR2 (6)

FIRST_NAMEVARCHAR2 (50)

LAST_NAMENOT NULLVARCHAR2 (50)

ADDRESSVARCHAR2 (50)

CITYVARCHAR2 (25)

STATEVARCHAR2 (3)

You want to display details of all members who reside in states starting with the letter A followed by exactly one character.

Which SQL statement must you execute?

A. SELECT * FROM MEMBERS WHERE state LIKE \’%A_*;

B. SELECT * FROM MEMBERS WHERE state LIKE \’A_*;

C. SELECT * FROM MEMBERS WHERE state LIKE \’A_%\’;

D. SELECT * FROM MEMBERS WHERE state LIKE \’A%\’;

Correct Answer: B


Question 8:

Which three statements are true regarding the WHERE and HAVING clauses in a SQL statement? (Choose three.)

A. WHERE and HAVING clauses cannot be used together in a SQL statement.

B. The HAVING clause conditions can have aggregate functions.

C. The HAVING clause conditions can use aliases for the columns.

D. The WHERE clause is used to exclude rows before the grouping of data.

E. The HAVING clause is used to exclude one or more aggregated results after grouping data.

Correct Answer: ABD


Question 9:

Examine the structure of the PROMOTIONS table: (Choose the best answer.)

Management requires a report of unique promotion costs in each promotion category. Which query would satisfy this requirement?

A. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1

B. SELECT promo_category, DISTINCT promo_cost FROM promotions

C. SELECT DISTINCT promo_cost, promo_category FROM promotions

D. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;

Correct Answer: A


Question 10:

View the exhibit and examine the ORDERS table. ORDERS Name Null? Type ORDER ID NOT NULL NUMBER(4)

ORDATE DATE

DATE

CUSTOMER ID

NUMBER(3)

ORDER TOTAL

NUMBER(7,2)

The ORDERS table contains data and all orders have been assigned a customer ID. Which statement would add a NOT NULL constraint to the CUSTOMER_ID column?

A. ALTER TABLE ordersMODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);

B. ALTER TABLE ordersADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);

C. ALTER TABLE ordersMODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);

D. ALTER TABLE ordersADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;

Correct Answer: C


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