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 Published Date: 04/27/2019

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Question 1:

Which two statements are true about cursor variables? (Choose two.)

A. A cursor variable points to the current row in the result set of a multirow query stored in a work area.

B. A cursor variable is an explicitly named work area in which the results of different multirow queries can be stored.

C. A cursor variable can be used only if a query is performed and its results are processed in the same subprogram.

D. A cursor variable can be used to perform a query in one subprogram, and process the results in a different subprogram.

Correct Answer: AD

Question 2:

You executed this command to gather information about the memory allocation for storing query results:

SQL> execute dbms_result_cache.memory_report

View the Exhibit and examine the output for the execution of the DBMS_RESULT_CACHE.MEMORY_REPORT procedure.

Which two statements are true about the output in the Exhibit? (Choose two.)

A. In total, four blocks are used by the result cache.

B. Currently 52 KB is allocated to the result cache.

C. Currently 32 KB is allocated to the result cache.

D. The result cache can be increased by 65628 bytes.

Correct Answer: CD

Question 3:

Which three statements are true about hierarchical profiling? (Choose three.)

A. It provides function-level summaries.

B. It produces an aggregated report of the SQL and PL/SQL execution times.

C. It is useful for understanding the structure and control flow of complex programs.

D. It can be used to identify hotspots and tuning opportunities in PL/SQL applications.

E. It generates trace information for PL/SQL programs in the PLSQL_TRACE_EVENTS table.

Correct Answer: ACD

Question 4:

Examine this function: Execute the query:

SELECT remap_schema FROM dual;

Which is the correct output from the query?

A. CREATE TABLE “EMP” (“EMPNO” NUMBER (4,0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4,0), “HIREDATE”DATE, “SAL” NUMBER (7,2) , “COMM” NUMBER (7,2), “DEPTNO” NUMBER (2,0),CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT CELL_FLASH_CACHE DEFAULT)TABLESPACE “USERS” ENABLE,CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”) REFERENCES “DEPT” (“DEPTNO”) ENABLE) SEGMENT CREATION IMMEDIATEPCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255NOCOMPRESS LOGGINGSTORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)TABLESPACE “USERS”

B. CREATE TABLE “EMP” (“EMPNO” NUMBER (4, 0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4, 0), “HIREDATE” DATE, “SAL” NUMBER (7, 2), “COMM” NUMBER (7, 2), “DEPTNO” NUMBER (2, 0),CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)USING INDEX ENABLE,CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)REFERENCES “DEPT” (“DEPTNO”) ENABLE)

C. CREATE TABLE “SCOTT”. “EMP” (“EMPNO” NUMBER (4, 0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4, 0), “HIREDATE” DATE, “SAL” NUMBER (7, 2), “COMM” NUMBER (7, 2), “DEPTNO” NUMBER (2, 0),CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)USING INDEX ENABLE,CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”)REFERENCES “DEPT” (“DEPTNO”) ENABLE)

D. CREATE TABLE “EMP” (“EMPNO” NUMBER (4,0), “ENAME” VARCHAR2 (10), “JOB” VARCHAR2 (9), “MGR” NUMBER (4,0), “HIREDATE”DATE, “SAL” NUMBER (7, 2) , “COMM” NUMBER (7, 2), “DEPTNO” NUMBER (2,0),CONSTRAINT “PK_EMP” PRIMARY KEY (“EMPNO”)USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255STORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT CELL_FLASH_CACHE DEFAULT)TABLESPACE “SYSAUX” ENABLE,CONSTRAINT “FK_DEPTNO” FOREIGN KEY (“DEPTNO”) REFERENCES “DEPT” (“DEPTNO”) ENABLE) SEGMENT CREATION IMMEDIATEPCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255NOCOMPRESS LOGGINGSTORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)TABLESPACE “SYSAUX”

Correct Answer: B

Question 5:

Examine this block:

Which two will be correct after line 5?

A. va. LAST and va. LIMIT will return the same value.

B. va. LAST and va. COUNT will return the same value.

C. va. LIMIT and va. COUNT will return the same value.

D. va. LIMIT and va. NEXT (199) will return the same value.

E. va. LAST will return 200.

F. va. NEXT (199) will return NULL.

Correct Answer: AC

Latest 1Z0-148 Dumps1Z0-148 Exam Questions1Z0-148 Braindumps

Question 6:

Which two blocks of code execute successfully?

A. DECLARETYPE tab_type IS TABLE OF NUMBER;my_tab tab_type;BEGINmy_tab (1) :=1;END;

B. DECLARETYPE tab_type IS TABLE OF NUMBER;my_tab tab_type := tab_type(2);BEGINmy_tab(1) :=55;END;

C. DECLARETYPE tab_type IS TABLE OF NUMBER;my_tab tab_type;BEGINmy_tab. EXTEND (2);my_tab (1) := 55;END;

D. DECLARETYPE tab_type IS TABLE OF NUMBER;my_tab tab_type;BEGINmy_tab := tab_type ();my_tab (1) := 55;END;

E. DECLARETYPE tab_type IS TABLE OF NUMBERmy_tab tab_type := tab_type (2, NULL,50);BEGINmy_tab.EXTEND (3, 2);END;

Correct Answer: BD

Question 7:

Examine these statements:

Which two corrections will allow this anonymous block to execute successfully?

A. Add wk# .NEXT; before the 7thline.

B. Add i PLS_INTEGER; before the 3rdline.

C. Add wk#. EXTEND (1); before the 5thline.

D. Change line #2 to wk# tp_test# := tp_test# (tp_rec# ());

E. Replace lines 5 and 6 with wk# (i) := tp_rec# (i, i);

Correct Answer: CE

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